Question:
calculate the number of bromide ions in 3 moles of mercury [II] bromide
Answer:
Mercury [II] bromide in ionic form
HgBr2 →Hg+ + 2Br-
1 molecule of HgBr2 contain 2Br-
Hence, 1 mole of HgBr2 contain 2Br-
Therefore, 3 mole of HgBr2 contain = 2 x3 = 2Br- = 6 x 6.023 x 1023 = 1.807 x 1023 ions
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